find_factors {lazy.symbolic} | R Documentation |
*, /, %*%, %\@%
.Decompose a Term into Multiplicative Factors separated by
*, /, %*%, %\@%
.
find_factors(expr, markso = 1, sort = 0, debug = 0)
expr |
An expression string (scalar, vector or matrix) |
markso |
= 0 not to mark the special opeartors |
sort |
= 1 to sort the factors according to their names |
debug |
= 1 to print the intermediate result |
It is assumed that there is just one character in between % and %.
The i-th factor with the preceding operator of expr is
substr( expr0, fromto[i,1], fromto[i,2] ) where
expr0 is the blank compressed expr.
The prefix operator associated with the i-th factor is oper[i].
The original expression can be recovered as:
res <- find_factors( expr ) expr <- paste( mapply( paste, res$oper, res$factor, sep="" ), collapse="" )
or
expr <- paste( paste( res$oper, res$factor, sep="" ), collapse="" )
or
#'
expr <- paste( apply(res$tab,1, function(x){paste(x,collapse="")} )
, collapse="")
The unbalanced parens, if any, will be neglected but recorded in
valid
flag.
The factors can be sorted according to their names as follows:
res <- find_factors("A*d/a/c", sort=1) exprs <- paste( paste( res$oper, res$factor, sep="" ), collapse="" ) res <- find_factors("A*c/(x+y)/d", sort=1) exprs <- paste( paste( res$oper, res$factor, sep="" ), collapse="" )
A list consisting of
# of factors (nfactors),
a vector of operators (oper),
a vector of factors (factor),
location of each oper+factor (fromto),
a matrix of operators and terms (tab) ,
a vector of validity flag of each term (valid),
ok flag (ok=1 if the input expr is equal to the reconstructed one.)
find_factors( "a*b/c*(d-e)*f(n)" )
find_factors( c("a*b/c*(d-e)*f(n)", "-2.13*a") )
find_factors( "a%*%b/c%*%(d-e)%*%f(n)" )
find_factors( "ab%*%cd*(b%p%q+a%m%c)/c*d/a%T%b" )
# error
find_factors( "a+b" )